![]() ![]() Supported Poker Rooms: PokerStars, Full Tilt Poker, Merge Network, Winamax, iPoker, 888 Poker, Party Poker (limited functionality), Revolution Poker, Winning Poker Network.System Requirements : Windows 7, 8 or 10, macOS 10.11 or higher, 4GB RAM (8GB recommended), 2 GHz processor, 1GB of free disk space.Product: Poker Copilot – online poker tracking software.Use the formula: (3*opponent's bet/raise + pot before opponent's bet/raise) to calculate a raise to pot size, and: 2 * opponent's bet raise + pot before opponent's bet/raise) to calculate a raise by pot size. The key question is if your room has you raise 'to' or 'by' a given amount. You should now know how to calculate a pot size raise. If Player 1 folds, Player 2 will have to pay $90 to stay in a $180 pot and only be getting 2:1 pot odds. The size of your raise is calculated as follows:Ģ * Player 2's raise + Pot before Player 2's raise (including Player 1's bet) If you were to raise to give Player 1 2:1 pot odds, Player 2 would be able to stay in the hand fairly cheaply. This will give Player 1 even worse odds, since he has to pay $20 more to call than Player 2. You decide to raise so that Player 2 will only be getting 2:1 pot odds. Remember, your goal is to protect and give both opponents poor pot odds. There are $20 in the pot as the flop is revealed. You are in position and facing two opponents. We will conclude with an example of raising by pot size in a multiway pot (this is always done the same way, both before and after the flop). You can then calculate pot size raises as follows:Ģ * size of opponent's bet/raise + size of the pot before your opponent's bet/raise was made. If you wish to raise to $80 after having already invested $10 earlier in the betting round, you must enter $70, since you wish to raise by $70 (to a total of $80). Raises are then calculated as: Amount entered + amount needed to call a previous bet/raise. Things are a big different at some rooms (such as Titan Poker), which have players raise by a given amount. Assuming Player 1 folds (he will only be getting 1.6:1 pot odds), Player 2 will be getting exactly 2:1. ![]() Player 2 would have to pay $50 ($65 -$15) to call. + Pot size before Player 2's raise (including Player 1's bet): + $20 A pot size raise in this example would therefore be: And since the principle of protection is based on giving all opponents poor pot odds (if possible), you raise by the amount that gives Player 2 2:1 pot odds (assuming Player 1 folds). If, on the other hand, you raise so that Player 1 will only be getting 2:1 pot odds, Player 2 will be getting much better odds. If you make a pot size raise so that Player 2 will only be getting 2:1 pot odds at best, Player 1 will be getting even worse odds, since he has to pay $10 more to call than Player 2. There are $15 in the pot at the start of the betting round. You are in position in a 3-way pot on the flop. Now it's time to talk about the "at best." Let's look at what happens when more than one opponent is in the hand and both have made different sized wagers in the current betting round. ![]()
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